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2 January, 14:06

Find three consecutive even integers. such that 7 times of first integer is 14 more than the sum of second and third integers.

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  1. 2 January, 14:11
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    Let the even number be 2n, 2n+2, 2n+4 where n=1,2,3, ...

    Given Condition is

    7 (2n) = (2n+2+2n+4) + 14

    14n=4n+6+14

    14n-4n=20

    10n=20

    n=20/10

    n=2

    So the Numbers are 2x2, 2x2+2, 2x2+4

    Answer is 4,6,8
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