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22 November, 11:53

t = 0.005x^2 + 0.002x

t = seconds x = objects

Q = How many objects are required to keep the computer busy in exactly 9 seconds?

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  1. 22 November, 12:02
    0
    t = 0.005x² + 0.002x

    9 = 0.005x² + 0.002x

    0 = 0.005x² + 0.002x - 9

    x = - (0.002) ± √ ((0.002) ² - 4 (0.005) (-9))

    2 (0.005)

    x = - 0.002 ± √ (0.000004 + 0.18)

    0.01

    x = - 0.002 ± √ (0.180004)

    0.01

    x = - 0.002 ± 2√ (0.053911)

    0.01

    x = - 0.2 ± 200√ (0.053911)

    The number of objects that is required to keep the computer busy in exactly 9 seconds is - 0.2 ± 200√ (0.053911).
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