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13 October, 18:22

Thomas creates the table shown to represent the function ƒ (x) = x2 + 3x - 10. determine the zeros of the equation.

A) x=-5 and x=2

B) x=0 and x=-3

C) x=0 and x=-10

D) x-2 and x=-1

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  1. 13 October, 18:24
    0
    Answer: A

    Explanation: The zeroes of f (x) are the value/s of x such that f (x) = 0. So, we need to find the values of x in the equation f (x) = 0.

    Note that

    f (x) = 0

    ⇔ x² + 3x - 10 = 0

    By factoring into binomials, x² + 3x - 10 = (x + 5) (x - 2). Thus,

    x² + 3x - 10 = 0

    ⇔ (x + 5) (x - 2) = 0

    ⇔ x + 5 = 0 or x - 2 = 0

    ⇔ x = - 5 or x = 2

    Hence, the zeroes of x are - 5 and 2.
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