4z+27+5x=14y

If x, y and z each represent a different digit from 0 - 9 what is the value of (x) (y) (z)

In order for the equation to work, x must be odd. Trying different values of x, we find 5 solutions:

(x, y, z) = (1, 4, 6), (3, 5, 7), (5, 6, 8), (7, 5, 2), (9, 6, 3)

Then the product xyz could be any of 24, 105, 240, 70, or 162.