The owner of a chain of clothing stores is comparing the monthly profit earned in the past year from four different store locations. She

calculated the mean and standard deviation of the monthly profit, in dollars for each location as shown in the table.

Location A Location B Location

Location D

Mean = 23,124.70 Mean = 24,842.18 Mean = 20,833.33 Mean = 21,432.82

SD = 1.553.43 SD = 1,617.20 SD = 1.462.15 SD = 1,512.10

For which store location does 68% of the data lie between $19.371.18 and $22.295.48?

A

B

location A

location B

location

C

D.

location D

Question

Faulkner

Mathematics

7 February, 19:57

The owner of a chain of clothing stores is comparing the monthly profit earned in the past year from four different store locations. She

calculated the mean and standard deviation of the monthly profit, in dollars for each location as shown in the table.

Location A Location B Location

Location D

Mean = 23,124.70 Mean = 24,842.18 Mean = 20,833.33 Mean = 21,432.82

SD = 1.553.43 SD = 1,617.20 SD = 1.462.15 SD = 1,512.10

For which store location does 68% of the data lie between $19.371.18 and $22.295.48?

A

B

location A

location B

location

C

D.

location D

+1

Answers (1)

Know the Answer?

Zachariah Huerta · Answer 1

Answer choice C, location C

Step-by-step explanation:

If you add or subtract the standard deviation to the monthly profit, then you get $19,371.18 and $22,295.48. This shows that the deviation withholds most of the data given

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