Elvis Hancock

Mathematics

1 February, 21:03

Given

/qquad / overline{OA}/perp/overline{OC}

OA

⊥

OC

start overline, O, A, end overline, / perp, start overline, O, C, end overline

/qquad m / angle BOC = 6x - 6^/circm∠BOC=6x-6

∘

m, angle, B, O, C, equals, 6, x, minus, 6, degrees

/qquad m / angle AOB = 5x + 8^/circm∠AOB=5x+8

∘

m, angle, A, O, B, equals, 5, x, plus, 8, degrees

Find m/angle BOCm∠BOCm, angle, B, O, C: