Ask Question
1 February, 21:03

Given

/qquad / overline{OA}/perp/overline{OC}

OA



OC

start overline, O, A, end overline, / perp, start overline, O, C, end overline

/qquad m / angle BOC = 6x - 6^/circm∠BOC=6x-6



m, angle, B, O, C, equals, 6, x, minus, 6, degrees

/qquad m / angle AOB = 5x + 8^/circm∠AOB=5x+8



m, angle, A, O, B, equals, 5, x, plus, 8, degrees

Find m/angle BOCm∠BOCm, angle, B, O, C:

+5
Answers (1)
  1. 1 February, 21:18
    0
    It would be 2x over 6
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Given /qquad / overline{OA}/perp/overline{OC} OA ⊥ OC start overline, O, A, end overline, / perp, start overline, O, C, end overline /qquad ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers