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8 November, 12:33

Consider a sequence that follows a times 5 pattern: 1, 5, 25, 125, ...

a. Write a formula for the nnth term of the sequence. Be sure to specify what value of n your formula starts with.

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  1. 8 November, 12:44
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    Answer: Hello mate!

    Here we have the sequence: 1, 5, 25, 125, ... etc

    the first term is an 1 = 5^0

    the second term is 5 = 5^1

    the third term is 25 = (5*5) = 5^2

    the fourth term is 125 = 5*25 = (5*5*5) = 5^3

    then the n-th term is five to the power of (n - 1)

    The n-th term of the sequence is:

    p (n) = 5^ (n-1)

    and the recursive relation is:

    p (n) = 5p (n-1)

    where p (1) = 1

    where n ≥ 1
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