Of the people who fished at Clearwater Park today,

56

had a fishing license, and

14

did not. Of the people who fished at Mountain View Park today,

72

had a license, and

8

did not. (No one fished at both parks.)

Suppose that one fisher from each park is chosen at random. What is the probability that the fisher chosen from Clearwater had a license and the fisher chosen from Mountain View did not have a license?

Do not round your answer.

Question

Rogers

Mathematics

3 February, 19:23

Of the people who fished at Clearwater Park today,

56

had a fishing license, and

14

did not. Of the people who fished at Mountain View Park today,

72

had a license, and

8

did not. (No one fished at both parks.)

Suppose that one fisher from each park is chosen at random. What is the probability that the fisher chosen from Clearwater had a license and the fisher chosen from Mountain View did not have a license?

Do not round your answer.

+5

Answers (1)

Know the Answer?

Jayda Newton · Answer 1

The probability is 2/25 or an 8% chance. By taking the probability of the fishers from Clearwater (56/70) and multiplying that by the probability of the non fishers from Mountain view (8/80) we can find the total probability of the situation.