For safety reasons, four different alarm systems were installed in the vault containing the safety deposit boxes at a beverly hills bank. each of the four systems detects theft with a probability of. 99 independently of the others. the bank, obviously, is interested in the probability that when a theft occurs, at least oneof the four systems will detect it. this probability is equal to:

Question

Leyla Townsend

Mathematics

15 July, 21:58

For safety reasons, four different alarm systems were installed in the vault containing the safety deposit boxes at a beverly hills bank. each of the four systems detects theft with a probability of. 99 independently of the others. the bank, obviously, is interested in the probability that when a theft occurs, at least oneof the four systems will detect it. this probability is equal to:

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Dandy · Answer 1

The probability any one system works is 0.99

So the probability of any one system failing is 1-0.99 = 0.01, so basically a 1% chance of failure for any one system

Multiply out the value 0.01 with itself four times

0.01*0.01*0.01*0.01 = 0.000 000 01

I'm using spaces to make the number more readable

So the probability of all four systems failing is 0.00000001

Subtract this value from 1 to get

1 - 0.00000001 = 0.99999999

The answer is 0.99999999 which is what we'd expect. The probability of at least one of the systems working is very very close to 1 (aka 100%)