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30 July, 16:20

What is the standard form of the equation of the circle x2 - 2x y2 - 8y - 8 = 0?

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Answers (2)
  1. 30 July, 16:37
    0
    The standard form of the equation of the circle is:

    (x - p) ² + (y - q) ² = r²; where p, q are the coordinates of the circle's center and r is the radius of the circle.

    x² - 2 x + y² - 8 y - 8 = 0

    (x² - 2 x + 1) + (y² - 8 y + 16) - 1 - 16 - 8 = 0

    We completed the square of the binomial.

    (x - 1) ² + (y - 4) ² = 1 + 16 + 8

    Answer:

    The standard form of the equation is (x - 1) ² + (y - 4) ² = 25.
  2. 30 July, 16:38
    0
    2*2-8-8=0

    X*Y-y

    You multiply 2 subtract 8 two times
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