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4 September, 13:53

Factor the polynomial. 3x^6y^2+81y^2

A) 3y^2 (x^2+3) (x^4-3x^2-9)

B) 3y^2 (x^2-3) (x^4+3*+9)

C) prime polynomial

D) 3y^2 (x^2+3) (x^4-3x^2+9)

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Answers (2)
  1. 4 September, 13:54
    0
    3x ⁶ y ² + 81y ² =

    3y² (x⁶+27) =

    3y² ((x²) ³+3³) =

    3y² (x²+3) (x⁴-3x²+9)

    Answer: D.
  2. 4 September, 13:56
    0
    Answer is choice D

    The reason why is ...

    3x^6y^2 + 81y^2 = 3y^2 (x^6 + 27)

    3x^6y^2 + 81y^2 = 3y^2 ((x^2) ^3 + 3^3)

    3x^6y^2 + 81y^2 = 3y^2 (x^2 + 3) ((x^2) ^2 - (x^2) * 3 + 3^2)

    3x^6y^2 + 81y^2 = 3y^2 (x^2 + 3) (x^4 - 3x^2 + 9)
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