F (x) = x^3+x^2-42x what are the zeros

F (x) = x^3+x^2-42x

Roots

Solve for x over the real numbers

x³+x²-42x=0

Factor the left-hand side

The left-hand side factors into a product with three terms

x (x-6) (x+7) = 0

Find the roots of each term separately

Split into three equations

x-6=0 x=0 x+7=0

Look at the first equation and solve for x

Add 6 to both sides

x=6 x=0 x+7=0

Look at the third equation and solve for x

Subtract 7 from both sides

Answer:

x=6 x=0 x=-7