Solve 2x^2 + 3x - 7 = x^2 + 5x + 39 for x.

A. x = - 6 + square root 82

B. x = - 6+2 square root 17

C. x = 1 + square root 33

D. x = 1 + square root 47

2x^2 + 3x - 7 = x^2 + 5x + 39 =

2x^2 - x^2 + 3x - 5x - 7 - 39 = 0

x^2 - 2x - 46 = 0

x = (-b (+-) sqrt b^2 - 4ac) / 2a

x = ( - (-2) (+-) sqrt - 2^2 - 4 (1) (-46) / 2 (1)

x = 2 (+-) sqrt 4 + 184) / 2

x = 2 (+-) sqrt 188) / 2

x = 1 (+-) sqrt 47