A student has some $1 and $5 bills in his wallet. He has a total of 18 bills that are worth $50. How many of each type of bill does he have?

There were 5 bills of '1' and 9 bills of '5'.

Step-by-step explanation:

let the number of '1' bill be x

let the number of '5' bill be y.

Total number of bills = 14

x + y = 14 ... [1]

Worth of 14 bills = 50

So, x/times 1+y/times 5=/$50x*1+y*5=$50

x+5y=50x+5y=50 ... [2]

x + y = 14

x = 14 - y

Putting value of x in [2]:

14 - y + 5y=5014-y+5y=50

y=/frac{50-14}{4}=9y=

4

50-14

=9

y = 9

x = 14-y = 14 - 9 = 5

There were 5 bills of '1' and 9 bills of '5'.

Answer: He has 8 $5 dollar bills and 10 ones

Step-by-step explanation: 8*5=40 1*10=10