To win the game, Elena has to roll an even number first and a number less than 3 second. Her probability of winning is 6/36.

Marta has a lower probability of winning than Elena has. Which could be the outcome that Marta needs to win the game? Check all that apply.

rolling a sum of 7

rolling a sum of 6

rolling a sum of 2 or a sum of 9

rolling a sum that is greater than 9

rolling a sum that is greater than 2 but less than 5

Question

Isabela Luna

Mathematics

9 June, 13:04

To win the game, Elena has to roll an even number first and a number less than 3 second. Her probability of winning is 6/36.

Marta has a lower probability of winning than Elena has. Which could be the outcome that Marta needs to win the game? Check all that apply.

rolling a sum of 7

rolling a sum of 6

rolling a sum of 2 or a sum of 9

rolling a sum that is greater than 9

rolling a sum that is greater than 2 but less than 5

+1

Answers (2)

Know the Answer?

Onyx · Answer 1

B. rolling a sum of 6

C. rolling a sum of 2 or a sum of 9

E. rolling a sum that is greater than 2 but less than 5

Beckham Pollard · Answer 2

Prob (Marta winning) Prob (Elena winning) : Case 4th

Step-by-step explanation:

Elena outcomes of winning, first even no. & second no. = 3 : (2,1), (2,2), (4,1), (4,2), (6,1), (6,2). So, Probability (Elena willing) = favourable outcomes / total outcomes = 6 / 36

Margie dice sum '7' outcomes = (2,5), (5,2), (3,4), (4,3). So, Prob = 4/36 Margie dice sum '6' outcomes = (1,5), (5,1), (2,4), (4,2), (3,3). So, Prob = 6/36 Margie dice sum '2' or '9' outcomes = (1,1), (3,6), (6,3), (4,5), (5,4). Prob = 5/36 Margie dice sum '>9' outcomes = (3,6), (6,3), (4,5), (5,4), (4,6), (6,4), (5,5), (5,6), (6,5), (6,6). Prob = 10/36 Margie dice sum '>2,<5' outcomes = (1,2), (2,1), (2,2), (1,3), (3,1) = 4 / 36