What are the vertical asymptotes of the function f (x) = the quantity of 2 x plus 8, all over x squared plus 5 x plus 6?

You'd find the vertical asymptotes by seeing where the denominator equals zero; you can do so by factoring the denominator.

In this case, you can factor the denominator into (x+3) (x+2), so if you set each of those equal to zero you can find the equations of the vertical asymptotes (x=-3 and x=-2).