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26 November, 11:32

Given:

2x-3y+z=0

3x+2y=35

4y-2z=14

Which of the following is a solution to the given system?

(2, 3, 5)

(3, 2, 0)

(1, 16, 0)

(7, 7, 7)

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Answers (1)
  1. 26 November, 11:36
    0
    If x and y are either 2 or 3 it would not fit 3x+2y=35.

    so the first two solutions are out.

    Try the third one 16*4 is 64. 64-0 is not 14 so the third one is out too.

    The answer is (7,7,7)
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