Ask Question
18 March, 09:58

The condition proves that ∆ABC and ∆EFG are congruent by the SAS criterion.

If AB ≠ EF, the criterion for congruency is violated. In this situation, angle C angle G.

+1
Answers (1)
  1. 18 March, 10:17
    0
    If AB ≠ EF, the criterion for congruency is violated. In this situation, angle C angle G are not equal:

    angle C ≠ angle G
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “The condition proves that ∆ABC and ∆EFG are congruent by the SAS criterion. If AB ≠ EF, the criterion for congruency is violated. In this ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers