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10 November, 01:43

Write log (x^2-9) - log (x+3) as a single logarithm.

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  1. 10 November, 02:11
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    One way: log (A) - log (B) = log (A/B) right?

    So, log (x^2-9 / (x+3))

    Now x^2-9 = (x+3) * (x-3), and x^2-9 / (x+3) = x-3,

    so log (x^2-9) - log (x+3) = log (x-3),

    Indeed for all x but for x = - 3, but probably no one asks you about that detail?
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