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11 April, 08:08

Ding three consecutive even integers such that the sum of twice the smallest and three times the largest is 42

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  1. 11 April, 08:37
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    6,8,10

    Step-by-step explanation:

    Two consecutive even integers would have difference of 2

    Hence we can assume the three consecutive integers to be of the form

    a-2, a and a+2

    Smallest number = a-2 and

    Largest number = a+2

    Twice the smallest number + 3 times largest number = 42 (given)

    2 (a-2) + 3 (a+2) = 42

    2a-4+3a+6 = 42

    5a + 2 = 42

    Subtract 2 and then divide by 5

    5a = 40 and a = 8

    Hence the three numbers are 6,8 and 10
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