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15 April, 04:07

Use natural logrithms to solve 6e^ (2x) - 9 = 23

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  1. 15 April, 04:32
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    Hello:

    6e^ (2x) - 9 = 23

    6e^ (2x) = 32

    e^ (2x) = 32/6 = 16/3

    2x = ln (16/3/

    x = (1/2) ln (16/3)
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