Mathematics

14 April, 13:54

The architect stands 6 feet from a climbing frame, looking up at the top of the frame at an angle of 63.43°. It is 5 and a half feet from ground to the architect's eyes. The vertical distance from eye level to the top of the climbing frame is _ feet. The height of the entire climbing frame is _ feet.

1.)

a) 12

b) 8.9

c. 4.5

d. 6.8

2.)

a) 17.5

b) 12.3

c) 14.4

d) 10

+4

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