Which number supports the given conjecture?

If a number is divisible by both 2 and 3, then the number is also divisible by 6.

A.

16

B.

23

C.

27

D.

36

A. 16 is divisible by 2 but not divisible by 3

B. 23 is not divisible neither by 2 nor 3

C. 27 is not divisible by 2, however it's divisible by 3

D. 36 is divisible both by 2 and 3

So the only number we can focus on is 36:

36 : 2 = 18

36 : 3 = 12

36 : 6 = 6

Answer: D, 36 supports the given conjecture.

D. 36 because 36 / 2 = 18 36 / 3 = 12 36 / 6 = 6