Ann, Hong and josh served a total of 120 orders Monday at school cafeteria: josh served 4 times as many Orders as Hong. Ann served 6 fewer orders than Hong. How many orders did they each serve

Answer: Josh served 84 lunches, Hong served 21 lunches, and Ann served 15.

Step-by-step explanation:

So there are 120 lunches. We can just call the amount of lunches Josh served, x. So, we know that Hong served a fourth of the lunches Josh did, so we can label him as 1/4 x. We also know that Ann served 6 less than Hong, so she would be 1/4x - 6. Next, we put all that into an equation.

120 = x + 1/4x + 1/4x - 6.

Now we have to get the x by itself, so you add 6 to the left side.

126 = x + 1/4x + 1/4x

Now we combine all of the x's.

126 = 1.5x

We then divide 126 by 1.5 to find the x value.

X = 84

So because X is the amount Josh served, we know he served 84 lunches.

But Hong served 1/4 of the amount Josh served, so you divide 84 by 4 to get 21 lunches. Finally, Ann served 6 less than Hong, so you subtract 6 from 21 to get 15 lunches.