Solve (x + 2 - 6).

1. 1 < x < 3

2. x 1

3. {all real numbers}

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Mathematics

1 August, 18:10

Solve (x + 2 - 6).

1. 1 < x < 3

2. x 1

3. {all real numbers}

+3

Answers (1)

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Jorden Carson · Answer 1

1. x

Step-by-step explanation:

x + 2 < 5 subtract 2 from both sides

x + 2 - 2 < 5 - 2

x < 3

x - 7 > - 6 add 7 to both sides

x > 1

From x 1 we have 1 < x < 3

Solve (x + 2 - 6).1. 1 < x < 32. x 13. {all real numbers}

Solve (x + 2 - 6).

1. 1 < x < 3

2. x 1

3. {all real numbers}