The ratio of a number and 4 times that number is equal to the ratio of 5 times the number and 95 more than a number

I just need the problem

1/4 = (5n) / (n + 95)

Step-by-step explanation:

If all the numbers referred to are the same number, we can use n to represent it. Then, "the ratio of a number and 4 times that number" is n / (4n) = 1/4. "The ratio of 5 times the number and 95 more than the number" is (5n) / (n+95)

The equation for the problem can be written ...

1/4 = (5n) / (95+n)

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If you're a purist, you might leave the factors of "a number" in the first raio and write it ...

n / (4n) = (5n) / (95+n)

Solving this gets you to a quadratic form that has the extraneous solution n=0.