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3 February, 10:46

On a particular day, the wind added 4 miles per hour to Jaime's rate when she was rowing with the wind and subtracted 4 miles per hour from her rate on her return trip. Jaime found that in the same amount of time she could row 54 miles with the wind, she could go only 30 miles against the wind. What is her normal rowing speed with no wind?

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  1. 3 February, 11:04
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    Nice so

    remember

    t=d/s

    a (b+c) = ab+ac

    time=distance/speed

    lets say s=jamie's normal speed

    speed agains wind=s-4

    speed with wind=s+4

    30 miles is agains wind

    distance is 54 with wind

    t=d/s

    t=30 / (s-4)

    t=54 / (s+4)

    since they are both equal to t, set them equal to each other

    30 / (s-4) = 54 / (s+4)

    multipliy both sides by (s+4) (s-4)

    30 (s+4) = 54 (s-4)

    distribute

    30s+120=54s-216

    subtract 30s from both sides

    120=24s-216

    add 216 to both sides

    336=24s

    divide both sides by 24

    14=s

    answer is 14 miles per hour without wind
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