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24 February, 06:20

Jalen Brunson is shooting free throws. Making or missing free throws doesn't change the probability that he will make his next one, and he makes his free throws 90% percent of the time. What is the probability of Jalen Brunson making his next 2 free throw attempts?

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  1. 24 February, 06:22
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    The probability is 0.81

    Step-by-step explanation:

    In this question, we are tasked with calculating the probability that Jalen makes his next two free throws.

    P (of making free throw) = 90% = 90/100 or 0.9

    P (of missing free throw) = 1 - P (of making free throw) = 1-0.9 = 0.1

    Now we want to calculate that probability of making the next two free throws.

    That would be = p (of making next throw) * p (of making next two throws) = 0.9 * 0.9 = 0.81
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