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17 October, 13:35

4. The specific heat of aluminum is 0.902 J/g. If a metal smith has 300g of aluminum and wants to melt it down to make a lock. He increases the temperature from 20 to 200. How much heat does he need to apply?

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  1. 17 October, 13:54
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    Q = 48708 J

    Step-by-step explanation:

    Q = mcΔt

    Q = 300 g x (0.902 J/g°C) x (200°C - 20°C)

    Q = 300 g x (0.902 J/g°C) x (180°C)

    Q = 48708 J
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