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28 October, 15:15

A particular fruit's weights are normally distributed, with a mean of 651 grams and a standard deviation of 27 grams. if you pick 49 fruit at random, what is the probability that their mean weight will be between 642 grams and 657 grams

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  1. 28 October, 15:42
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    Answer: About 21.64% of the fruit will be between 642 and 657 grams.

    To solve this problem, we will have to find the probability for each z-score on the normal distribution. Then, subtract them to find the difference.

    Lower End:

    -9/27 = - 0.33 for the z-score which is a probability of 0.3707

    Upper End:

    6/27 = 0.22 for the z-score which is a probability of 0.5871.

    0.5871 - 0.3707 = 0.2164

    Or about 21.64%
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