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4 August, 18:43

Consider the function g (x) = integral of t^3+1 from pi to x. Calculate the derivative g' (2) at the position x=2

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  1. 4 August, 18:46
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    Answer:9

    Step-by-step explanation:

    g (x) = t^3+1

    g (2) = (2) ^3+1

    =8+1

    g (2) = 9
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