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30 December, 06:43

A mixture contains 21.7 g NaCl,

3.74 g KCl, and 9.76 g LICI.

How many total moles are in this

mixture?

+3
Answers (1)
  1. 30 December, 07:09
    0
    Total moles = 0.6504 moles

    Step-by-step explanation:

    Molar mass of NaCl = Molar mass of Na + Molar mass of Cl

    Molar mass of NaCl = 22.99 + 35.45 = 58.44 grams/moles

    No. of mole of Nacl = grams/molar mass

    No. of mole of Nacl = 21.7/58.44 = 0.371 mol

    Similarly calculate for other two

    Molar mass of KCl = 39.1 + 35.45 = 74.55 grams/moles

    No. of mole of Kcl = 3.74/74.55 = 0.0502 mol

    Molar mass of LiCl = 6.941 + 35.45 = 42.39 grams/moles

    No. of moles of LiCl = 9.76/42.39 = 0.2302 mol

    Total moles = 0.371 + 0.0502 + 0.2302

    Total moles = 0.6504 moles
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