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Chaz Stanton
Mathematics
19 May, 00:05
XY=4n+3, YZ=2n-7, XZ=22
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Matthew Munoz
19 May, 00:32
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Choose one of the equations, then try and rewrite in terms of 1 Unknown, eg I've chosen XZ = 22 and am going to write it in terms of X
XZ = 22
Z = 22/X (this is writing Z in terms of X)
So ... X (22/X) = 22
22/X=22X
22 = 22X^2 ( * ^2 is to the power 2)
Therefore X = 1
And Z = 22
Use this to solve the remaining equations
1xY = 4n + 3
22Y = 2n - 7
Then rearrange and do simultaneous equations
22Y - 66 = 88n
22Y + 7 = 2n
-73 = 86n
n = - 73/86
It is very very likely that I have made a mistake somewhere here given the strange number I have for n but I spent far too long on this not to post it ahaha, even if the numbers are incorrect this is the general method I would follow
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