Given y=x^3-2x^2-15; find the relative minimum.

Question

Rashad

Mathematics

9 April, 17:27

Given y=x^3-2x^2-15; find the relative minimum.

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Answers (1)

Know the Answer?

Ryan Shaffer · Answer 1

The min is at x=4/3

Step-by-step explanation:

Take the first derivitave. Set that equation equal to zero. Then take the second derivative. Take the x values and put them into the second derivative. If the value is +, that means a rel min. If it is -, that means rel max.