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16 November, 15:32

If the probability of A given B is 0.8 and the probability of A is 0.12 what is the probability of B

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  1. 16 November, 15:54
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    We can't tell from the information given. What we do know is

    P (A ∩ B) = P (A|B) P (B)

    We're given the conditional probability but not the probability of the conjunction.

    If we were told P (A|B) = 0.8 and P (A ∩ B) = 0.12 we could conclude

    P (B) = P (A ∩ B) / P (A|B) = 0.12/0.8 = 0.15

    but that wasn't the problem asked.
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