Between what two integers does √98 lie?

Question

Campbell Marsh

Mathematics

23 November, 01:17

Between what two integers does √98 lie?

+2

Answers (2)

Know the Answer?

Zaire Estes · Answer 1

one way is this:

if the 2 integers are x and y, then

x<√98
if we assume that x and y aer both positive then

square everybody

x²<98
solve each

x²<98

square root both sides

x<9.89

since x must be an integer, x=9

98
squaer root both side

9.89
since y must be an integer, y=10

√98 lies between 9 an 10

Hassan Shaw · Answer 2

Which perfect square is less than 98? More than 98?

9^2 = 81, and 10^2 = 100.

Since 81 < 98 < 100,

√81 < √98 < √100.

Therefore, 9 < √98 < 10∫

√98 lies between the integers 9 and 10.