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Lindsey Joyce
Mathematics
30 September, 22:54
Factor completely: x3 - x2y - xy2 + y3
+3
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Korbin Mcgee
30 September, 23:09
0
X^3-x^2-xy^2+y^3
the first factor is (x+y)
dividing the polynomial by the factor we get:
(x^2-2xy+y^2)
factoring the above quadratic equation we get:
x (x-y) - y (x-y)
= (x-y) (x-y)
thus the answer is:
x^3-x^2-xy^2+y^3 = (x-y) (x-y) (x+y)
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