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22 June, 03:58

In ΔBCD, the measure of ∠D=90°, the measure of ∠B=75°, and CD = 97 feet. Find the length of BC to the nearest tenth of a foot.

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  1. 22 June, 04:17
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    100.42 feet

    Step-by-step explanation:

    Since the triangle has a right angle, we may find the length of the unknown side using the trigonometric notations SOH CAH TOA where

    SOA stands for

    Sin Ф = opposite side/hypotenuses side

    Cosine Ф = adjacent side/hypotenuses side

    Tangent Ф = opposite side/adjacent side

    Given that the measure of ∠D=90°, the measure of ∠B=75°, and CD = 97 feet

    CD is the opposite side facing ∠B, BC is the hypotenuse side hence

    Sin 75 = 97/BC

    BC = 97/Sin 75°

    = 100.42 feet
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