Factor the following polynomial: x2-5x+6

(x-2) (x-3)

x=2

x=3

Step-by-step explanation:

This seems like factorisation

X^2-5x+6

To factorise, you will look for two numbers that when multiplied together it will give 6 and when added it will give - 5

Back to the question, the two numbers that can be used to multiple 6 and when added it will gives - 5 is - 3*-2

x^2-3x-2x+6

x (x-3) - 2 (x-3)

(x-3) (x-2)

Which can be solved further,

(x-3) = 0

Add 3 to both sides

x=3

(x-2) = 0

Add 2 to both sides

x=2