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Chace Griffith
Mathematics
13 March, 08:27
Find
∫^[infinity]_-[infinity] x / (1+x^2) ^2 dx.
+2
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1
)
Tyrese Rivas
13 March, 08:41
0
Step-by-step explanation:
integral (x / (1+x^2) ^2) dx
= (1/2) integral (2x / (1+x^2) ^2) dx
= (1/2) [-1 / (1+x^2) ] + c
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