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17 December, 07:58

For what value of m is the equation true?

X^2-6x+5=m + (x-3) - 6

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Answers (1)
  1. 17 December, 08:19
    0
    1. Simplify brackets

    x^2-6x+5=m+x-3-6

    2. Simplify m+x-3-6 to m+x-9

    x^2-6x+5=m+x-9

    3. Subtract x from both sides

    x^2-6x+5-x=m-9

    4. Simplify x^2-6x+5-x to x^2-7x+5

    x^2-7x+5=m-9

    5. Add 9 on both sides

    x^2-7x+5+9=m

    6. Simplify x^2-7x+5+9 to x^2-7x+14

    x^2-7x+14=m

    7. Switch sides

    m=x^2-7x+14

    You can always check by putting the new value of m into the equation (I already did that, so you don't have to)

    1.2. Simplify brackets

    x^2-6x+5=x^2-7x+14+3-3-6

    2.2. Cancel x^2 on both sides

    -6x+5=-7x+14-x-3-6

    3.2. Simplify - 7x+14+x-3-6 to - 6x+14-3-6

    -6x+5=-6x+14-3-6

    4.2. Simplify - 6x+14-3-6 to - 6x+5

    -6x+5=-6x+5

    5.2 Since both sides are equal, the value for m is x^2-7x+14

    Have a nice day : D
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