What is the equation of the line that passes through (4, - 1) and (-2, 3) ?

2 x + 3 y - 5 = 0

-2 x + 3 y - 5 = 0

2 x - 3 y - 5 = 0

Step-by-step explanation:

m = (y2-y1) / (x2-x1)

m = (3 - (-1)) / (-2-4)

m = (3+1) / -6

m=4/-6

simplify

m=-2/3

y-y1=m (x-x1)

y - (-1) = -2/3 (x-4)

y+1=-2/3 (x-4)

y+1=-2/3x+8/3

y=-2/3x+8/3-1

y=-2/3x+8/3-3/3

y=-2/3x+5/3

y - (-2/3x) = 5/3

y+2/3x=5/3

2/3x+y=5/3

3 (2/3x+y) = 3 (5/3)

2x+3y=5

2x+3y-5=0