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28 January, 05:36

The vertex of this parabola is at (2, - 1). When the y-value is 0, the x-value is 5. What is the coefficient of the squared term in the parabola's equation?

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  1. 28 January, 05:50
    0
    The coefficient would be 1/9.

    We first write this in vertex form:

    y=a (x-h) ²+k, where (h, k) is the vertex. Using our vertex, we have:

    y=a (x-2) ²-1

    We know that the parabola goes through (5, 0), so we can use these coordinates to find the value of a:

    0=a (5-2) ²-1

    0=a (3) ²-1

    0=9a-1

    Add 1 to both sides:

    0+1=9a-1+1

    1=9a

    Divide both sides by 9:

    1/9 = 9a/9

    1/9 = a
  2. 28 January, 06:01
    0
    The answer is 3 (Apex)
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