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18 January, 12:11

What are the real roots to the given power equation: 3 (x-4) ^4/3+16=64

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  1. 18 January, 12:16
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    3 (x-4) ^4/3+16=64 (x-4) * 4+16=64 4x-4*4 4x-16+16=64

    4x=64 4x/4=64/4 x=64/4

    x=16
  2. 18 January, 12:36
    0
    3 (x-4) ^4/3+16 = 64

    3 (x-4) ^4/3 = 48

    (x-4) ^4/3 = 16

    (x-4) ^4 = 4096

    (x-4) ^2 = 64

    x^2-8x+16 = 64

    x^2-8x-48 = 0

    (x+4) (x-12) = 0

    x = - 4 or x = 12
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