What times what equals 24 and sums to 11

Xy = 24

x + y = 11

x + y = 11

- x - x

y = - x + 11

xy = 24

x (-x + 11) = 24

x (-x) + x (11) = 24

-x² + 11x = 24

- 24 - 24

-x² + 11x - 24 = 0

-1 (x²) - 1 (-11x) - 1 (24) = 0

-1 (x² - 11x + 24) = 0

-1 - 1

x² - 11x + 24 = 0

x² - 8x - 3x + 24 = 0

x (x) - x (8) - 3 (x) + 3 (8) = 0

x (x - 8) - 3 (x - 8) = 0

(x - 3) (x - 8) = 0

x - 3 = 0 or x - 8 = 0

+ 3 + 3 + 8 + 8

x = 3 or x = 8

x + y = 11

3 + y = 11

- 3 - 3

y = 8

(x, y) = (3, 8)

x + y = 11

8 + y = 11

- 8 - 8

y = 3

(x, y) = (8, 3)

The two numbers that add up to 11 and multiply to 24 are 8 and 3.

Ok since _x_=24+11 well lets rephrase the equation _x_+11=24 so lets find _ and _ we can find it easily by subtract 24-11=13 but if you multiply 13x1 = 13 add 13+1 = 24 your answer would be 13,1