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8 August, 20:47

Determine algebraically whether the function g (x) = x^2 is even odd or neither

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  1. 8 August, 20:48
    0
    g (x) = x^2

    g (-x) = (-x) ^2 ... replace every x with - x

    g (-x) = x^2 ... squaring a negative makes it positive

    So because g (x) = g (-x) for every x, this means g (x) is an even function. For polynomials, if every exponent is even, then the entire polynomial is even as well.

    Note: if a function is even, then it won't be odd or vice versa unless the function is the zero function. In other words, g (x) = 0 is both even and odd.
  2. 8 August, 20:58
    0
    I think its 2 because its 2 so you will put 2
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