The area of a certain rectangle is 288 yd2. the perimeter is 68 yd. what are the dimensions of the rectangle?

P = 2 (L + W)

P = 68

68 = 2 (L + W)

68/2 = L + W

34 = L + W

34 - L = W

A = L * W

A = 288

W = 34 - L

288 = L (34 - L)

288 = 34L - L^2

L^2 - 34L + 288 = 0

(L - 16) (L - 18)

L - 16 = 0

L = 16

L - 18 = 0

L = 18

not exactly sure which (length or width), but one is 16 yds and one is 18 yds