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Davian Conway
Mathematics
29 September, 06:21
Factor out the greatest common factor 6ab+9bc
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Richards
29 September, 06:32
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Ab+ac=a (b+c)
a is common factor
factor
6ab=2*3*a*b
9bc=3*3*b*c
common factor is 3*b or 3b
3b (2a) + 3b (3c) = 3b (2a+3c)
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Nia
29 September, 06:39
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3b (2a + 3c) Both 6 and 9 are divisible by three and the b is in both parts of expression
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