Classify the system of equations. 2x + y - 3 = 0 x + y - 1 = 0

Solve the following system:

{-3 + 2 x + y = 0 | (equation 1)

{-1 + x + y = 0 | (equation 2)

Express the system in standard form:

{2 x + y = 3 | (equation 1)

{x + y = 1 | (equation 2)

Subtract 1/2 * (equation 1) from equation 2:

{2 x + y = 3 | (equation 1)

{0 x+y/2 = (-1) / 2 | (equation 2)

Multiply equation 2 by 2:

{2 x + y = 3 | (equation 1)

{0 x+y = - 1 | (equation 2)

Subtract equation 2 from equation 1:

{2 x+0 y = 4 | (equation 1)

{0 x+y = - 1 | (equation 2)

Divide equation 1 by 2:

{x+0 y = 2 | (equation 1)

{0 x+y = - 1 | (equation 2)

Collect results:

Answer: {x = 2, y = - 1