The perimeter of a rectangle is 58. The length is 1 more than 2 1/2 times the width. Find the dimensions of the rectangle

The formula of the perimeter of a rectangle is given as

P=2L+2W

where L is the length and W is the width. Substitution of the given values will yield,

58=2L+2W (1)

The next thing that we have to do is to translate the relationship between the two variables, L and W, into a mathematical equation.

So we have

L=2.5W+1 (2)

Now we have two equations, we also have two unknowns, so this problem is solvable. Substitution of equation (2) in (1) yields

58=2 (2.5W+1) + 2W

58=5w+2+2w

58=7W+2

56=7W

8=W

Substitution of this value to equation (2) yields

L=2.5 (8) + 1

L=21

So, the dimensions of the rectangle are:, specifically, width is equal to 8 while length is equal to 21.